Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.8 The Complex Numbers - 10.8 Exercise Set: 46

Answer

$-6+14i$

Work Step by Step

Using $a(b+c)=ab+ac$, or the Distributive Property, and the properties of radicals, the given expression, $ 2i(7+3i) ,$ simplifies to \begin{array}{l}\require{cancel} 2i(7)+2i(3i) \\\\= 14i+6i^2 \\\\= 14i+6(-1) \\\\= 14i-6 \\\\= -6+14i .\end{array}
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