Answer
$1+5i$
Work Step by Step
Using $(a+b)(c+d)=ac+ad+bc+bd$, or the product of 2 binomials, and the properties of radicals, the given expression, $
(1+i)(3+2i)
,$ simplifies to
\begin{array}{l}\require{cancel}
1(3)+1(2i)+i(3)+i(2i)
\\\\=
3+2i+3i+2i^2
\\\\=
3+5i+2(-1)
\\\\=
3+5i-2
\\\\=
1+5i
.\end{array}