Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.8 The Complex Numbers - 10.8 Exercise Set: 49

Answer

$1+5i$

Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$, or the product of 2 binomials, and the properties of radicals, the given expression, $ (1+i)(3+2i) ,$ simplifies to \begin{array}{l}\require{cancel} 1(3)+1(2i)+i(3)+i(2i) \\\\= 3+2i+3i+2i^2 \\\\= 3+5i+2(-1) \\\\= 3+5i-2 \\\\= 1+5i .\end{array}
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