Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.8 The Complex Numbers - 10.8 Exercise Set: 75

Answer

$1-2i$

Work Step by Step

Multiplying the denominator by $i$, the given expression, $ \dfrac{7i+14}{7i} ,$ is equivalent to \begin{array}{l}\require{cancel} \dfrac{7i+14}{7i}\cdot\dfrac{i}{i} \\\\= \dfrac{7i(i)+14(i)}{7i(i)} \\\\= \dfrac{7i^2+14i}{7i^2} \\\\= \dfrac{7(-1)+14i}{7(-1)} \\\\= \dfrac{-7+14i}{-7} \\\\= \dfrac{-7(1-2i)}{-7} \\\\= \dfrac{\cancel{-7}(1-2i)}{\cancel{-7}} \\\\= 1-2i .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.