Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.8 The Complex Numbers - 10.8 Exercise Set - Page 686: 53

Answer

$2-46i$

Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$, or the product of 2 binomials, and the properties of radicals, the given expression, $ (7-2i)(2-6i) ,$ simplifies to \begin{array}{l}\require{cancel} 7(2)+7(-6i)-2i(2)-2i(-6i) \\\\= 14-42i-4i+12i^2 \\\\= 14-46i+12(-1) \\\\= 14-46i-12 \\\\= 2-46i .\end{array}
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