Chapter 10 - Exponents and Radicals - 10.8 The Complex Numbers - 10.8 Exercise Set - Page 686: 29

$7+2i$

Removing the grouping symbols and then adding the real parts and the imaginary parts, the given expression, $ (9+5i)-(2+3i) ,$ simplifies to \begin{array}{l}\require{cancel} 9+5i-2-3i \\\\= (9-2)+(5i-3i) \\\\= 7+2i .\end{array}