College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.8 - Solving Basic Equations - P.8 Exercises: 49

Answer

$z=\frac{3}{97}$

Work Step by Step

$\displaystyle \frac{1}{z}-\frac{1}{2z}-\frac{1}{5z}=\frac{10}{z+1}$ We multiply both sides by $10z(z+1)$: $10(z+1)-5(z+1)-2(z+1)=10(10z)$ Then we distribute and simplify: $3(z+1)=100z$ $3z+3=100z$ $3=97z$ And solve for $z$: $z=\frac{3}{97}$
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