College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.8 - Solving Basic Equations - P.8 Exercises: 37

Answer

$x=\frac{4}{3}$

Work Step by Step

$(x-1)(x+2)=(x-2)(x-3)\displaystyle$ We distribute both sides: $x^{2}+x-2=x^{2}-5x+6$ And simplify: $x-2=-5x+6$ And combine $x$ terms: $6x=8$ And solve for $x$: $x=\frac{4}{3}$
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