Answer
$t=10$
Work Step by Step
$\displaystyle \frac{1}{3-t}+\frac{4}{3+t}+\frac{15}{9-t^{2}}=0$
We multiply by $(3+t)(3-t)$:
$(3+t)+4(3-t)+15=0$
Then we distribute and simplify:
$3+t+12-4t+15=0$
$-3t+30=0$
$-3t=-30$
And solve for $t$:
$t=10$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter P, Prerequisites - Section P.8 - Solving Basic Equations - P.8 Exercises - Page 60: 50
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