College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.8 - Solving Basic Equations - P.8 Exercises: 100

Answer

$a=\frac{1}{2}(b^{2}+b)$

Work Step by Step

$\displaystyle \frac{a+1}{b}=\frac{a-1}{b}+\frac{b+1}{a}$ We multiply both sides by $ab$: $a(a+1)=a(a-1)+b(b+1)$ And distribute: $a^{2}+a=a^{2}-a+b^{2}+b$ And simplify: $2a=b^{2}+b$ And solve for $a$: $a=\frac{1}{2}(b^{2}+b)$
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