College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.8 - Solving Basic Equations - P.8 Exercises: 59

Answer

$\left\{-2\sqrt{2}, 2\sqrt{2}\right\}$

Work Step by Step

Add $64$ to both sides: $8x^2=64$ Divide $8$ on both sides to obtain: $x^2=8$ Factor $8$ so that one factor is a perfect square: $x=\pm \sqrt{4(2)} \\x=\pm \sqrt{2^2(2)} \\x=\pm 2\sqrt{2}$ Thus, the solution set of the given equation is $\left\{-2\sqrt{2}, 2\sqrt{2}\right\}$.
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