## College Algebra 7th Edition

$\displaystyle y=\frac{21}{11}$
$\displaystyle \frac{2}{3}y+\frac{1}{2}(y-3)=\frac{y+1}{4}$ We multiply by 12: $8y+6(y-3)=3(y+1)$ And distribute: $8y+6y-18=3y+3$ And simplify: $14y-18=3y+3$ And combine $y$ terms: $11y=21$ And solve for $y$: $\displaystyle y=\frac{21}{11}$