College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.8 - Solving Basic Equations - P.8 Exercises: 39

Answer

$x=\frac{14}{13}$

Work Step by Step

$(x-1)(4x+5)=(2x-3)^{2}\displaystyle$ We distribute: $4x^{2}+x-5=4x^{2}-12x+9$ And simplify: $x-5=-12x+9$ And combine $x$ terms: $13x=14$ And solve for $x$: $x=\frac{14}{13}$
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