College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.6 - Solving Other Types of Equations - 1.6 Exercises: 16

Answer

$x=0$ or $x=3$ or $x=-2$

Work Step by Step

We solve by factoring: $x^{4}-x^{3}-6x^{2}=0$ $x^{2}(x^{2}-x-6)=0$ $x^{2}(x-3)(x+2)=0$ $x^{2}=0$ or $x-3=0$ or $x+2=0$ $x=0$ or $x=3$ or $x=-2$
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