Answer
$x=0$ or $x=3$ or $x=-2$
Work Step by Step
We solve by factoring:
$x^{4}-x^{3}-6x^{2}=0$
$x^{2}(x^{2}-x-6)=0$
$x^{2}(x-3)(x+2)=0$
$x^{2}=0$ or $x-3=0$ or $x+2=0$
$x=0$ or $x=3$ or $x=-2$
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