College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.6 - Solving Other Types of Equations - 1.6 Exercises - Page 138: 12

Answer

$t=0$ or $t=\displaystyle \frac{\sqrt[3]{2}}{5}$

Work Step by Step

We solve by factoring: $125t^{10}-2t^{7}=0$ $t^{7}(125t^{3}-2)=0$ $t^7=0$ or $125t^{3}-2=0$ $t=0$ or $t^3=2/125$ $t=0$ or $t=\displaystyle \sqrt[3]{\frac{2}{125}}=\frac{\sqrt[3]{2}}{5}$
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