Answer
$x=0$ or $x=2$ or $x=3$
Work Step by Step
We solve by factoring:
$x^{3}-5x^{2}+6x=0$
$x(x^{2}-5x+6)=0$
$x(x-2)(x-3)=0$
$x=0$ or $x-2=0$ or $x-3=0$
$x=0$ or $x=2$ or $x=3$
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