Answer
$x=5$ or $x=\pm\sqrt{2}$
Work Step by Step
We solve with factoring by grouping:
$x^{3}-5x^{2}-2x+10=0$
$x^{2}(x-5)-2(x-5)=0$
$(x-5)(x^{2}-2)=0$
$x-5=0$ or $x^{2}-2=0$
$x=5$ or $x=\pm\sqrt{2}$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 1, Equations and Graphs - Section 1.6 - Solving Other Types of Equations - 1.6 Exercises - Page 138: 21
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