College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.6 - Solving Other Types of Equations - 1.6 Exercises: 30

Answer

$x=1$

Work Step by Step

$\displaystyle \frac{2x}{x^{2}+1}=1$ We cross-multiply: $2x=x^{2}+1$ $x^{2}-2x+1=0$ And solve by factoring: $(x-1)^{2}=0$ $x=1$
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