College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.6 - Solving Other Types of Equations - 1.6 Exercises: 7

Answer

$x=0$ or $x=-5$ or $x=5$

Work Step by Step

We solve by factoring and using the fact that $a^2-b^2=(a+b)(a-b)$: $x^{3}=25x$ $x^{3}-25x=0$ $x(x^{2}-25)=0$ $x(x+5)(x-5)=0$ $x=0$ or $x+5=0$ or $x-5=0$ $x=0$ or $x=-5$ or $x=5$
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