## College Algebra 7th Edition

$x=0$ or $x=-5$ or $x=5$
We solve by factoring and using the fact that $a^2-b^2=(a+b)(a-b)$: $x^{3}=25x$ $x^{3}-25x=0$ $x(x^{2}-25)=0$ $x(x+5)(x-5)=0$ $x=0$ or $x+5=0$ or $x-5=0$ $x=0$ or $x=-5$ or $x=5$