College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.6 - Solving Other Types of Equations - 1.6 Exercises: 25

Answer

$z=1$

Work Step by Step

$z+\displaystyle \frac{4}{z+1}=3$ We multiply through by $z+1$ and solve by factoring: $z(z+1)+4=3(z+1)$ $z^2+z+4=3z+3$ $z^2+z+4-3z-3=0$ $z^2-2z+1=0$ $(z-1)(z-1)=0$ $z=1$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.