College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.3: 76

Answer

-2.4456

Work Step by Step

Based on the change of base property for common logarithms, we know that $log_{b}M=\frac{log(M)}{log(b)}$. Therefore, $log_{.3}19=\frac{log(19)}{log(.3)}=\frac{1.2788}{-0.5229}\approx-2.4456$.
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