Answer
1
Work Step by Step
We know that $log(x)$ is a common logarithm with an understand base of 10.
Therefore, $log5+log2=log_{10}5+log_{10}2$.
Based on the product rule of logarithms, we know that $log_{b}(MN)=log_{b}M+log_{b}N$ (for $M\gt0$ and $N\gt0$).
Therefore, $log_{10}5+log_{10}2=log_{10}(5\times2)=log_{10}10$.
Based on the definition of the logarithmic function, we know that $y=log_{b}x$ is equivalent to $b^{y}=x$ (for $x\gt0$ and $b\gt0$, $b\ne1$).
Therefore, $log_{10}10=1$, because $10^{1}=10$.