## College Algebra (6th Edition)

$= 4\ln(x) + \frac{1}{2}\ln(x^{2}+3)-5\ln(x+3)$
$= \ln[\frac{x^{4}\sqrt {x^{2}+3}}{(x+3)^{5}}]$ $= \ln(x^{4}\sqrt {x^{2}+3}) - \ln((x+3)^{5})$ $=\ln(x^{4}) + \ln(\sqrt {x^{2}+3}) - 5\ln(x+3)$ $=4\ln(x) + \ln((x^{2}+3)^{\frac{1}{2}})-5\ln(x+3)$ $= 4\ln(x) + \frac{1}{2}\ln(x^{2}+3)-5\ln(x+3)$