College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.3: 38

Answer

$= 4\ln(x) + \frac{1}{2}\ln(x^{2}+3)-5\ln(x+3)$

Work Step by Step

$= \ln[\frac{x^{4}\sqrt {x^{2}+3}}{(x+3)^{5}}]$ $= \ln(x^{4}\sqrt {x^{2}+3}) - \ln((x+3)^{5})$ $=\ln(x^{4}) + \ln(\sqrt {x^{2}+3}) - 5\ln(x+3)$ $=4\ln(x) + \ln((x^{2}+3)^{\frac{1}{2}})-5\ln(x+3)$ $= 4\ln(x) + \frac{1}{2}\ln(x^{2}+3)-5\ln(x+3)$
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