Answer
$log_{5}7+log_{5}3$
Work Step by Step
Based on the product rule of logarithms, we know that $log_{b}(MN)=log_{b}M+log_{b}N$ (for $M\gt0$ and $N\gt0$).
Therefore, $log_{5}(7\times3)=log_{5}7+log_{5}3$.
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