Answer
$\frac{x^{11}}{81}$
Work Step by Step
$\frac{3^{-1}x^{4}}{3^{3}x^{-7}}=\frac{3^{-1}}{3^{3}}\times\frac{x^{4}}{x^{-7}}=3^{-1-3}\times x^{4-(-7)}=3^{-4}\times x^{4+7}=3^{-4}\times x^{11}=\frac{x^{11}}{3^{4}}=\frac{x^{11}}{81}$
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