Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.2 - Negative Exponents and Scientific Notation - Exercise Set: 61

Answer

$\Big(\dfrac{a^{-5}b}{ab^{3}}\Big)^{-4}=a^{24}b^{8}$

Work Step by Step

$\Big(\dfrac{a^{-5}b}{ab^{3}}\Big)^{-4}$ Evaluate the exponential expression: $\Big(\dfrac{a^{-5}b}{ab^{3}}\Big)^{-4}=\dfrac{a^{20}b^{-4}}{a^{-4}b^{-12}}=...$ Now, evaluate the division and simplify: $...=a^{20-(-4)}b^{-4-(-12)}=a^{24}b^{8}$
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