Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.2 - Negative Exponents and Scientific Notation - Exercise Set: 72

Answer

$ \frac{10}{7x^4}\times m^2$

Work Step by Step

The area of the triangle is $\frac{1}{2} \times \frac{4}{x} m \times \frac{5x^{-3}}{7}m$ $=\frac{1}{2} \times \frac{20x^{-3}}{7x} m^2 = \frac{10x^{-3}}{7x^1} m^2 = \frac{10x^{-3-1}}{7} m^2 = \frac{10}{7}\times x^{-4} \times m^2 = \frac{10}{7}\times \frac{1}{x^4} \times m^2 = \frac{10}{7x^4}\times m^2$
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