Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.2 - Negative Exponents and Scientific Notation - Exercise Set - Page 354: 56

Answer

$\frac{1}{32x^{5}}$

Work Step by Step

$\frac{2^{-3}x^{-4}}{2^{2}x}=\frac{2^{-3}}{2^{2}}\times \frac{x^{-4}}{x}=2^{-3-2}\times x^{-4-1}=2^{-5}\times x^{-5}=\frac{1}{2^{5}x^{5}}=\frac{1}{32x^{5}}$
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