Answer
$\frac{1}{32x^{5}}$
Work Step by Step
$\frac{2^{-3}x^{-4}}{2^{2}x}=\frac{2^{-3}}{2^{2}}\times \frac{x^{-4}}{x}=2^{-3-2}\times x^{-4-1}=2^{-5}\times x^{-5}=\frac{1}{2^{5}x^{5}}=\frac{1}{32x^{5}}$
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