Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.2 - Negative Exponents and Scientific Notation - Exercise Set: 69

Answer

$\dfrac{(a^{4}b^{-7})^{-5}}{(5a^{2}b^{-1})^{-2}}=\dfrac{25b^{33}}{a^{16}}$

Work Step by Step

$\dfrac{(a^{4}b^{-7})^{-5}}{(5a^{2}b^{-1})^{-2}}$ Evaluate the exponential expressions in the numerator and the denominator: $\dfrac{(a^{4}b^{-7})^{-5}}{(5a^{2}b^{-1})^{-2}}=\dfrac{a^{-20}b^{35}}{(5)^{-2}a^{-4}b^{2}}=...$ Evaluate the division and simplify: $...=5^{2}a^{-20-(-4)}b^{35-2}=25a^{-16}b^{33}=\dfrac{25b^{33}}{a^{16}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.