Answer
$\frac{z^{2}}{4}$
Work Step by Step
$\frac{4^{2}z^{-3}}{4^{3}z^{-5}}=\frac{4^{2}}{4^{3}}\times\frac{z^{-3}}{z^{-5}}=4^{2-3}\times z^{-3-(-5)}=4^{-1}\times z^{-3+5}=4^{-1}\times z^{2}=\frac{1}{4}\times z^{2}=\frac{z^{2}}{4}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 5 - Section 5.2 - Negative Exponents and Scientific Notation - Exercise Set - Page 354: 53
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