Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.2 - Negative Exponents and Scientific Notation - Exercise Set: 53

Answer

$\frac{z^{2}}{4}$

Work Step by Step

$\frac{4^{2}z^{-3}}{4^{3}z^{-5}}=\frac{4^{2}}{4^{3}}\times\frac{z^{-3}}{z^{-5}}=4^{2-3}\times z^{-3-(-5)}=4^{-1}\times z^{-3+5}=4^{-1}\times z^{2}=\frac{1}{4}\times z^{2}=\frac{z^{2}}{4}$
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