Answer
The power required to operate the tow is $2.96\times 10^4~W$.
Work Step by Step
We can convert the speed to units of m/s.
$v = (12.0~km/h)(\frac{1000~m}{1~km})(\frac{1~h}{3600~s}) = 3.33~m/s$
We can find the required power.
$P = F~v$
$P = (50)(mg)~sin(\theta)~v$
$P = (50)(70.0~kg)(9.80~m/s^2)~sin(15.0^{\circ})(3.33~m/s)$
$P = 2.96\times 10^4~W$
The power required to operate the tow is $2.96\times 10^4~W$.
