Answer
The light bulb uses $3.6\times 10^5~J$ of energy in one hour.
A 70-kg person would need to run with a speed of 101 m/s to have the same amount of kinetic energy.
Work Step by Step
$100 ~W = 100 ~J/s$
In one hour:
$E = (100~J/s)(3600~s) = 3.6\times 10^5~J$
The light bulb uses $3.6\times 10^5~J$ of energy in one hour.
We can find the speed of a 70-kg person with this amount of kinetic energy.
$\frac{1}{2}mv^2 = 3.6\times 10^5~J$
$v^2 = \frac{7.2\times 10^5~J}{m}$
$v = \sqrt{\frac{7.2\times 10^5~J}{70~kg}}$
$v = 101~m/s$
A 70-kg person would need to run with a speed of 101 m/s to have the same amount of kinetic energy.
