## University Physics with Modern Physics (14th Edition)

$P = F~v$ $P = mg~v = (700~kg)(9.80~m/s^2)(2.5~m/s)$ $P = 17,150 ~W$ We can find the fraction of the power used to make the airplane climb. $\frac{17,150~W}{75,000~W} = 0.23$ A fraction of 0.23 of the airplane's power is being used to make the airplane climb.