Answer
A fraction of 0.23 of the airplane's power is being used to make the airplane climb.
Work Step by Step
$P = F~v$
$P = mg~v = (700~kg)(9.80~m/s^2)(2.5~m/s)$
$P = 17,150 ~W$
We can find the fraction of the power used to make the airplane climb.
$\frac{17,150~W}{75,000~W} = 0.23$
A fraction of 0.23 of the airplane's power is being used to make the airplane climb.
