# Chapter 6 - Work and Kinetic Energy - Problems - Exercises - Page 196: 6.28

The player's foot must be in contact with the ball over a distance of 0.168 meters.

#### Work Step by Step

$W = K_2-K_1$ $F~d = \frac{1}{2}mv_2^2-\frac{1}{2}mv_1^2$ $d = \frac{m(v_2^2-v_1^2)}{2F}$ $d = \frac{(0.420~kg)((6.00~m/s)^2-(2.00~m/s)^2)}{(2)(40.0~N)}$ $d = 0.168~m$ The player's foot must be in contact with the ball over a distance of 0.168 meters.

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