University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 5 - Applying Newton's Laws - Problems - Exercises - Page 165: 5.67

Answer

The arms exert a force of 763 N during the acceleration.

Work Step by Step

We can find the acceleration. $y = \frac{1}{2}at^2$ $a = \frac{2y}{t^2} = \frac{(2)(0.15~m)}{(0.5~s)^2}$ $a = 1.2~m/s^2$ We can find the force $F$ exerted by the arms. $\sum F = ma$ $F -mg = ma$ $F = ma + mg = \frac{(680~N)(1.2~m/s^2)}{9.80~m/s^2}+680~N$ $F = 763~N$ The arms exert a force of 763 N during the acceleration.
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