University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 5 - Applying Newton's Laws - Problems - Exercises - Page 165: 5.62

Answer

The tension in the lower chain is $w$. The tension in the upper chain is $w$. $F = \frac{w}{2}$

Work Step by Step

Since the system is moving at a constant speed, the acceleration is zero. The tension $T_1$ in the lower chain is equal in magnitude to the weight $w$. That is, $T_1 = w$. We can find the tension $T_2$ in the rope. $2~T_2 = T_1$ $T_2 = \frac{T_1}{2} = \frac{w}{2}$ Since $F=T_2$ (the tension in the rope), we know that $F = \frac{w}{2}$ We can find the tension $T_3$ in the upper chain. $T_3 = 2~T_2 = 2~\frac{w}{2} = w$ The tension in the upper chain is $w$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.