Answer
On both sides of the reaction, baryon number, charge, strangeness, and lepton numbers are each conserved. By looking up these properties for the known particles, we deduce the values for the unknown particle. Then we use Table 44.3 to identify the particle.
Work Step by Step
a. The baryon number is 0, the charge is +e, the strangeness is 1, and all lepton numbers are zero. The particle is $K^+$.
b. The baryon number is 0, the charge is –e, the strangeness is 0, and all lepton numbers are zero. The particle is $\pi^-$.
c. The baryon number is -1, the charge is 0, the strangeness is 0, and all lepton numbers are zero. The particle is an antineutron, $\overline {n}$.
d. The baryon number is 0, the charge is +e, the strangeness is 0, $L_{\mu}=-1$, and the other lepton numbers are 0. The particle is $\mu^+$.
