University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 43 - Nuclear Physics - Problems - Exercises - Page 1478: 43.65

Answer

$1.0\times10^4$ years.

Work Step by Step

Following the example, let x be the number of elapsed half-lives. The problem tells us that $0.29=(\frac{1}{2})^x$. $$ln 0.29=x ln (1/2)$$ $$x=1.786$$ The elapsed time is 1.786 multiplied by the half-life of carbon-14, which is 5730 years. About $1.0\times10^4$ years have elapsed.
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