Answer
See explanation.
Work Step by Step
a. $\frac{10\times10^9 yr}{200000yr}=50000$ half lives.
b. One-half of the Tc decays in a half-life.
The fraction remaining would be $(\frac{1}{2})^{50000}\approx10^{-15051}\approx0$.
University Physics with Modern Physics (14th Edition)
by Young, Hugh D.; Freedman, Roger A.
Published by
Pearson
ISBN 10:
0321973615
ISBN 13:
978-0-32197-361-0
Chapter 43 - Nuclear Physics - Problems - Exercises - Page 1478: 43.59
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