University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 43 - Nuclear Physics - Problems - Exercises - Page 1476: 43.35

Answer

See explanation.

Work Step by Step

a. $175krad\frac{0.010Gy}{rad}=1.75kGy$. For x rays, RBE = 1.00. The equivalent dose equals the absorbed dose. 175 krad=175krem. The RBE for x-rays is 1.0, so by equation 43.20, the equivalent dose in sieverts is $RBE \times 1.75kGy=1.75kSv$. Calculate the absorbed energy. $\frac{1.75\times10^3J}{kg}(0.220kg)=385J$ b. 175 krad=1.75 kGy. The RBE for these electrons is 1.50, so by equation 43.20, the equivalent dose in sieverts is $RBE \times 1.75kGy=2.63kSv$. The RBE for these electrons is 1.50, so by equation 43.21, the equivalent dose in rem is $RBE \times 175krad=263krem$. The energy deposited would be the same as in part a. Incidentally, this corresponds to only a small temperature rise.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.