Answer
2.80 days.
Work Step by Step
We are told that $$(8318/min)2^{-4.00d/T_{1/2}}=3091/min$$
$$2^{-4.00d/T_{1/2}}=0.3716$$
$$ln2\frac{-4.00d}{T_{1/2}}=ln(0.3716)$$
$$ T_{1/2}=2.80d $$
University Physics with Modern Physics (14th Edition)
by Young, Hugh D.; Freedman, Roger A.
Published by
Pearson
ISBN 10:
0321973615
ISBN 13:
978-0-32197-361-0
Chapter 43 - Nuclear Physics - Problems - Exercises - Page 1476: 43.27
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