University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 34 - Geometric Optics - Problems - Exercises - Page 1154: 34.57

Answer

a. 6.06 cm. b. 4.125 mm.

Work Step by Step

a. Use the lens equation. $$\frac{1}{s}+\frac{1}{s’}=\frac{1}{f}$$ $$\frac{1}{s}+\frac{1}{-25.0cm}=\frac{1}{8.00cm}$$ $$s=6.06cm$$ b. Calculate the magnification. $$m=-\frac{s’}{s}=-\frac{-25.0cm }{6.06cm}=4.125$$ Find the height of the image. $$|y’|=|m||y|=(4.125)(1.00mm)=4.125mm$$
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