## University Physics with Modern Physics (14th Edition)

a. Use the lens equation. $$\frac{1}{s}+\frac{1}{s’}=\frac{1}{f}$$ $$\frac{1}{s}+\frac{1}{-25.0cm}=\frac{1}{8.00cm}$$ $$s=6.06cm$$ b. Calculate the magnification. $$m=-\frac{s’}{s}=-\frac{-25.0cm }{6.06cm}=4.125$$ Find the height of the image. $$|y’|=|m||y|=(4.125)(1.00mm)=4.125mm$$