University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 34 - Geometric Optics - Problems - Exercises - Page 1154: 34.54


See explanation.

Work Step by Step

a. The person is nearsighted. She can't see faraway objects. b. A diverging lens is needed. For an object very far from the person’s eye, the corrective lens forms a virtual image at the eye’s far point. c. Use the lens equation. $$\frac{1}{s}+\frac{1}{s’}=\frac{1}{f}$$ $$\frac{1}{\infty}+\frac{1}{-75.0cm}=\frac{1}{f}$$ $$f=-75.0cm$$ $$P=\frac{1}{f}=\frac{1}{-0.750m}=-1.33D$$
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