University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 34 - Geometric Optics - Problems - Exercises - Page 1154: 34.56

Answer

a. 4.17. b. 4.84 cm.

Work Step by Step

a. When the object is at the focal point, $M=\frac{25.0 cm}{f}$. This calculation assumes the near point is 25.0 cm from the eye. $$M=\frac{25.0 cm}{6.00cm}=4.17$$ b. Use the lens equation. $$\frac{1}{s}+\frac{1}{sā€™}=\frac{1}{f}$$ $$\frac{1}{s}+\frac{1}{-25.0cm}=\frac{1}{6.00cm}$$ $$s=4.84cm$$
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