University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 32 - Electromagnetic Waves - Problems - Exercises - Page 1073: 32.6

Answer

a. UVA frequencies range from $7.50\times10^{14}Hz$ to $9.38\times10^{14}Hz$. UVB frequencies range from $9.38\times10^{14}Hz$ to $1.07\times10^{15}Hz$. b. UVA wavenumbers range from $1.57\times10^{7} m^{-1}$ to $1.96\times10^{7} m^{-1}$. UVB wavenumbers range from $1.96\times10^{7} m^{-1}$ to $2.24\times10^{7} m^{-1}$.

Work Step by Step

Start with frequencies. $$f=\frac{c}{\lambda}=\frac{3.00\times10^{8}m/s}{400\times10^{-9}m}=7.50\times10^{14}Hz$$ $$f=\frac{c}{\lambda}=\frac{3.00\times10^{8}m/s}{320\times10^{-9}m}=9.38\times10^{14}Hz$$ $$f=\frac{c}{\lambda}=\frac{3.00\times10^{8}m/s}{320\times10^{-9}m}=1.07\times10^{15}Hz$$ We see that UVA frequencies range from $7.50\times10^{14}Hz$ to $9.38\times10^{14}Hz$. We see that UVB frequencies range from $9.38\times10^{14}Hz$ to $1.07\times10^{15}Hz$. On to wavenumbers. $$k=\frac{2 \pi}{\lambda}=\frac{2 \pi}{400\times10^{-9}m}=1.57\times10^{7} m^{-1}$$ $$k=\frac{2 \pi}{\lambda}=\frac{2 \pi}{320\times10^{-9}m}=1.96\times10^{7} m^{-1}$$ $$k=\frac{2 \pi}{\lambda}=\frac{2 \pi}{280\times10^{-9}m}=2.24\times10^{7} m^{-1}$$ We see that UVA wavenumbers range from $1.57\times10^{7} m^{-1}$ to $1.96\times10^{7} m^{-1}$. We see that UVB wavenumbers range from $1.96\times10^{7} m^{-1}$ to $2.24\times10^{7} m^{-1}$.
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