University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 32 - Electromagnetic Waves - Problems - Exercises - Page 1073: 32.13


See explanation.

Work Step by Step

a. $\lambda =\frac{c}{f}=\frac{3.00\times10^{8}m/s}{830\times10^{3}Hz }= 361m $. b. $k=\frac{2 \pi}{\lambda}=\frac{2 \pi}{361m}=1.74\times10^{-2} m^{-1}$. c. $\omega=2 \pi f=(2 \pi)( 830\times10^{3}Hz)= 5.22\times10^{6}rad/s$. d. $E_{max}=cB_{max}=0.0145V/m $.
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