Answer
a) $3.0\times10^8m/s$
b) $E_0=375V/m$, $B_0=1.25\times10^{-6}T$
c) $f=9.5\times10^{14}Hz$
$\lambda=3.2\times10^{-7}m$
$T=1.1\times10^{-15}s$
This light is not visible to humans.
Work Step by Step
a) This is an electromagnetic wave, so it has the speed of light $3.0\times10^8m/s$
b) $E_0=375V/m$, $E_0=cB_0$, so $B_0=\frac{E_0}{c}=\frac{375V/m}{3.0\times10^8m/s}=1.25\times10^{-6}T$
c) $f=\frac{5.97\times10^{15}rad/s}{2\pi}=9.5\times10^{14}Hz$
$\lambda=\frac{2\pi}{1.99\times10^7rad/m}=3.2\times10^{-7}m$
$T=\frac{1}{f}=1.1\times10^{-15}s$
The light with the smallest wavelength that is visible to humans is Violet, with a wavelength of $3.8\times10^{-7}m$ to $4.5\times10^{-7}m$. Therefore, this light is not visible to humans.
