University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 30 - Inductance - Problems - Exercises - Page 1014: 30.21


91.7 J.

Work Step by Step

First find the energy density, which depends on the strength of the magnetic field. $$u=\frac{B^2}{2\mu_0 }$$ $$u=\frac{(4.80T)^2}{2(4\pi \times10^{-7}Wb/m \cdot A)}=9.167\times10^6 J/m^3$$ The energy is the energy density, multiplied by the volume. $$U=u(V)=( 9.167\times10^6 J/m^3)(10.0\times10^{-6}m^3)=91.7J$$
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