Answer
91.7 J.
Work Step by Step
First find the energy density, which depends on the strength of the magnetic field.
$$u=\frac{B^2}{2\mu_0 }$$
$$u=\frac{(4.80T)^2}{2(4\pi \times10^{-7}Wb/m \cdot A)}=9.167\times10^6 J/m^3$$
The energy is the energy density, multiplied by the volume.
$$U=u(V)=( 9.167\times10^6 J/m^3)(10.0\times10^{-6}m^3)=91.7J$$
