University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 30 - Inductance - Problems - Exercises - Page 1014: 30.20

Answer

a. Energy = $1.296\times10^7 J$ in one day. b. $L=4.05\times10^{3}H$.

Work Step by Step

a. Energy = $(150J/s)(86400s/day)=1.296\times10^7 J$ in one day. b. $U=\frac{1}{2}LI^2$. Find the inductance. $$L=\frac{2U}{I^2}=\frac{2(1.296\times10^7 J)}{(80.0A)^2}=4.05\times10^{3}H$$ This is not practical.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.