## University Physics with Modern Physics (14th Edition)

a. $U=\frac{1}{2}LI^2=\frac{1}{2}(12.0H)(0.500A)^2=1.50J$. b. $P=I^2R=(0.500A)^2(180\Omega)=45.0W$ c. No. the stored energy depends on the current, which is constant. The energy being dissipated by the inductor comes from the emf source (e.g., battery) that drives the current.