## University Physics with Modern Physics (14th Edition)

The average velocity is $v_{av}=\frac{\Delta y}{\Delta t}$. Let the positive direction be upward. a. $v_{av}=\frac{\Delta y}{\Delta t}=\frac{1000m-63m}{4.75s}=197m/s$ b. $v_{av}=\frac{\Delta y}{\Delta t}=\frac{1000m-0m}{5.90s}=169m/s$